Analysis the rigid jointed plane frame

Degree of Static Indeterminancy.
Ds = R-E = 4-3 = 1
Assuming Ds = Number of redundant force R
|
Portion |
Origin |
Limit |
Mxx |
M1 |
|
DC |
D |
0-2 |
0 |
0 |
|
BC |
C |
0-4 |
-10X²/2 = -5X² |
+X |
|
BA |
B |
0-5 |
-20X – 1042 = -20X-80 |
4 |

Actual displacement at redundant = 0
[ D ] = [ ΔL1 ] + δ11 * R1
0 = - 2920 / EI + 101.33 / EI * R1
R1 = 2920 / 101.33 = 28.21 KN
