Program for Preemptive Priority CPU Scheduling

Implementing priority CPU scheduling. In this problem, we are using  the data structure for implementing priority scheduling.

Inthis problem smaller numbers denote higher priority.
The following functions are used in the given code below:

struct process {

   processID,

   burst time,

   response time,

   priority,

   arrival time.

}

void quicksort(process array[], low, high)– This function is used to arrange the processes in ascending order according to their arrival time.

int partition(process array[], int low, int high)– This function is used to partition the array for sorting.

void insert(process Heap[], process value, int *heapsize, int *currentTime)– It is used to include all the valid and eligible processes in the heap for execution. heapsize defines the number of processes in execution depending on the current time currentTime keeps record of the current CPU time.

void order(process Heap[], int *heapsize, int start)– It is used to reorder the heap according to priority if the processes after insertion of new process.

void extractminimum(process Heap[], int *heapsize, int *currentTime)– This function is used to find the process with highest priority from the heap. It also reorders the heap after extracting the highest priority process.
void scheduling(process Heap[], process array[], int n, int *heapsize, int *currentTime)– This function is responsible for executing the highest priority extracted from Heap[].

void process(process array[], int n)– This function is responsible for managing the entire execution of the processes as they arrive in the CPU according to their arrival time.

// CPP program to implement preemptive priority scheduling

#include <bits/stdc++.h>

using namespace std;

 

struct Process {

    int processID;

    int burstTime;

    int tempburstTime;

    int responsetime;

    int arrivalTime;

    int priority;

    int outtime;

    int intime;

};

 

// It is used to include all the valid and eligible

// processes in the heap for execution. heapsize defines

// the number of processes in execution depending on

// the current time currentTime keeps a record of

// the current CPU time.

void insert(Process Heap[], Process value, int* heapsize,

            int* currentTime)

{

    int start = *heapsize, i;

    Heap[*heapsize] = value;

    if (Heap[*heapsize].intime == -1)

        Heap[*heapsize].intime = *currentTime;

    ++(*heapsize);

 

    // Ordering the Heap

    while (start != 0 && Heap[(start - 1) / 2].priority >

                                  Heap[start].priority) {

        Process temp = Heap[(start - 1) / 2];

        Heap[(start - 1) / 2] = Heap[start];

        Heap[start] = temp;

        start = (start - 1) / 2;

    }

}

 

// It is used to reorder the heap according to

// priority if the processes after insertion

// of new process.

void order(Process Heap[], int* heapsize, int start)

{

    int smallest = start;

    int left = 2 * start + 1;

    int right = 2 * start + 2;

    if (left < *heapsize && Heap[left].priority <

                            Heap[smallest].priority)

        smallest = left;

     if (right < *heapsize && Heap[right].priority <

                           Heap[smallest].priority)

        smallest = right;

 

    // Ordering the Heap

    if (smallest != start) {

        Process temp = Heap[smallest];

        Heap[smallest] = Heap[start];

        Heap[start] = temp;

        order(Heap, heapsize, smallest);

    }

}

 

// This function is used to find the process with

// highest priority from the heap. It also reorders

// the heap after extracting the highest priority process.

Process extractminimum(Process Heap[], int* heapsize,

                       int* currentTime)

{

    Process min = Heap[0];

    if (min.responsetime == -1)

        min.responsetime = *currentTime - min.arrivalTime;

    --(*heapsize);

    if (*heapsize >= 1) {

        Heap[0] = Heap[*heapsize];

        order(Heap, heapsize, 0);

    }

    return min;

}

 

// Compares two intervals according to staring times.

bool compare(Process p1, Process p2)

{

    return (p1.arrivalTime < p2.arrivalTime);

}

 

// This function is responsible for executing

// the highest priority extracted from Heap[].

void scheduling(Process Heap[], Process array[], int n,

                int* heapsize, int* currentTime)

{

    if (heapsize == 0)

        return;

 

    Process min = extractminimum(Heap, heapsize, currentTime);

    min.outtime = *currentTime + 1;

    --min.burstTime;

    printf("process id = %d current time = %d\n",

           min.processID, *currentTime);

 

    // If the process is not yet finished

    // insert it back into the Heap*/

    if (min.burstTime > 0) {

        insert(Heap, min, heapsize, currentTime);

        return;

    }

 

    for (int i = 0; i < n; i++)

        if (array[i].processID == min.processID) {

            array[i] = min;

            break;

        }

}

 

// This function is responsible for

// managing the entire execution of the

// processes as they arrive in the CPU

// according to their arrival time.

void priority(Process array[], int n)

{

    sort(array, array + n, compare);

 

    int totalwaitingtime = 0, totalbursttime = 0,

        totalturnaroundtime = 0, i, insertedprocess = 0,

        heapsize = 0, currentTime = array[0].arrivalTime,

        totalresponsetime = 0;

 

    Process Heap[4 * n];

 

    // Calculating the total burst time

    // of the processes

    for (int i = 0; i < n; i++) {

        totalbursttime += array[i].burstTime;

        array[i].tempburstTime = array[i].burstTime;

    }

 

    // Inserting the processes in Heap

    // according to arrival time

    do {

        if (insertedprocess != n) {

            for (i = 0; i < n; i++) {

                if (array[i].arrivalTime == currentTime) {

                    ++insertedprocess;

                    array[i].intime = -1;

                    array[i].responsetime = -1;

                    insert(Heap, array[i], &heapsize, &currentTime);

                }

            }

        }

        scheduling(Heap, array, n, &heapsize, &currentTime);

        ++currentTime;

        if (heapsize == 0 && insertedprocess == n)

            break;

    } while (1);

 

    for (int i = 0; i < n; i++) {

        totalresponsetime += array[i].responsetime;

        totalwaitingtime += (array[i].outtime - array[i].intime -

                                         array[i].tempburstTime);

        totalbursttime += array[i].burstTime;

    }

    printf("Average waiting time = %f\n",

           ((float)totalwaitingtime / (float)n));

    printf("Average response time =%f\n",

           ((float)totalresponsetime / (float)n));

    printf("Average turn around time = %f\n",

           ((float)(totalwaitingtime + totalbursttime) / (float)n));

}

 

// Driver code

int main()

{

    int n, i;

    Process a[5];

    a[0].processID = 1;

    a[0].arrivalTime = 4;

    a[0].priority = 2;

    a[0].burstTime = 6;

    a[1].processID = 4;

    a[1].arrivalTime = 5;

    a[1].priority = 1;

    a[1].burstTime = 3;

    a[2].processID = 2;

    a[2].arrivalTime = 5;

    a[2].priority = 3;

    a[3].burstTime = 7;

    a[3].processID = 3;

    a[3].arrivalTime = 1;

    a[3].priority = 4;

    a[3].burstTime = 2;

    a[4].processID = 5;

    a[4].arrivalTime = 3;

    a[4].priority = 5;

    a[4].burstTime = 4;

    priority(a, 5);

    return 0;

}

Run on IDE

Output:

process id = 3 current time = 1

process id = 3 current time = 2

process id = 5 current time = 3

process id = 1 current time = 4

process id = 4 current time = 5

process id = 4 current time = 6

process id = 4 current time = 7

process id = 1 current time = 8

process id = 1 current time = 9

process id = 1 current time = 10

process id = 1 current time = 11

process id = 1 current time = 12

process id = 2 current time = 13

process id = 5 current time = 14

process id = 5 current time = 15

process id = 5 current time = 16

Average waiting time = 4.400000

Average response time =1.600000

Average turn around time = 7.200000