Statics
is the study of how forces are transmitted to and throughout stationary
objects. Let’s learn a little bit about how statics
is used by mechanical engineers to solve problems. Consider
a perfectly rigid bridge beam sitting on two supports (see Figure
1). Now suppose you decide to stand on it. The weight
of your body would push down on the beam, creating a system of forces that
act upon the beam. If the beam stays on its supports and doesn’t
move (it remains static), then the forces are said to be in
“equilibrium.” In other words, since the beam doesn’t move when
you stand on it, the sum of all the forces acting upon it are zero. Figure
1 So
what, you say? Well, this concept of forces in equilibrium helps
mechanical engineers analyze external and
internal forces acting on stationary objects that have importance to us in
real life, like bridges, machines, traffic signal masts, etc. This
analysis is used to calculate the magnitudes of all the forces acting on
these objects so they can design parts of the objects to be strong enough not
to break apart. Think about that next time you get ready to cross
a bridge in your car. To
show how this works, consider the bridge beam scenario I discussed
above. Suppose you weigh 150 pounds and you stand nine feet from
the left end of the bridge beam (see Figure 2). Your weight will
exert a downward force of 150 pounds upon the beam (let’s ignore the weight
of the beam in this case). The weight of your body creates
reaction forces on the beam at Support A and Support B. To
consider these reaction forces, the mechanical engineer would draw what is
called a “free body diagram” (see Figure 3).
Figure
2
Figure
3 The
reaction forces (FA and FB) at the supports A and
B push up on the bottom of the beam. If the beam remains static,
then the sum of the reaction forces will equal the 150 pound weight force
from your body. That is, the reaction forces cancel out the 150
pound force if the beam doesn’t move and they are said to be in equilibrium. But
in our example above, you’re not standing in the exact center of the beam, hence the two reaction forces
are not going to be equal. More of your body weight force is
bearing down on Support B and less on Support A. So how do you
determine the values of the reaction forces in a situation like this? You
consider “moments.” A
moment is mechanical engineering lingo for a force multiplied by a
distance. Moments want to rotate objects. This is an
important concept in statistics because if an object doesn’t move, it
certainly won’t rotate, so the sum of all the moments acting on the object
are zero. So, in the case of our bridge beam, the sum of the
moments acting on Support A would be zero, or mathematically speaking: Sum MA =
[(FA) x (0 Feet)] – [(150 Lb.) x (9 Feet)] + [(FB) x
(15 Feet)] = 0 Using
algebra, you can find the value for the reaction force at Support B: [0] –
[(150 Lb.) x (9 Feet)] + [(FB) x (15 Feet)] = 0 [(FB)
x (15 Feet)] = [(150 Lb.) x (9 Feet)] FB =
90 Lb. So
what about the reaction force at Support A? If you remember, I
said that if the bridge beam remains static, then the sum of all the forces
acting on it will be zero. Knowing that, you can use algebra to
solve for the reaction force at Support A: FA -150
Lb + FB = 0 FA =
150 Lb. – 90 Lb. = 60 Lb. So
that is the basic concept of statics. Remember, in statics,
nothing moves, so mechanical engineers use that to their advantage when
they analyze forces acting on objects.
|