When
we looked at our statics example a few Topics ago, it was convenient to
consider the bridge beam as being perfectly rigid. In the real
world, a bridge beam is not perfectly rigid. When it’s subjected
to external forces, like the weight of a truck sitting in the middle of it,
there is a tendency for it to bend, deform, change its
shape. If the external forces create bending and deformations that
are too much for the bridge beam material to handle, it will collapse. In
strengths of materials analysis, engineers must consider typical stresses
that will occur within objects like bridge beams, airplane wings, bolts, and
machine parts during use. Stress is a measure of force exerted per
unit area of a surface. Once the stresses are known, a material is
selected that is strong enough to keep the object from being bent, mashed,
stretched, and/or broken. To
illustrate this, let’s consider an example of a simple
stress. Suppose you want to design a truss rod for a highway
bridge like the one shown in Figure 1. Specifications require that
the rod be two inches in diameter. Its purpose is to hold the
sides of the bridge together when vehicles travel across it.
Figure
1 Now
suppose that the bridge is to handle traffic to and from and iron
mine. Let’s consider the scenario where a truck laden with iron
ore runs out of gas and comes to a stop in the middle of our
bridge. Under this load, static analysis reveals that the sides of
the bridge want to spread apart, putting a tension of 50,000 pounds force (Lbf.) on the truss rod as shown in Figure 2. Figure
2 Since
the external force acting upon the truss rod and the diameter of the rod
itself are both given, the engineer would merely have to select the
appropriate material for the rod that would fall within the desired
parameters, that is, so as to keep our rod from pulling apart when
anticipated stressors such as a heavy truck is on the bridge. The
first step would be to calculate the tensile stress within the rod
itself. By tensile stress, I mean the stress in the rod due to the
forces that are trying to pull it apart. In our example, this is
relatively easy to assess: Stress
= [Tensile Force] ÷ [Lateral Cross Sectional Area of the Rod] The
lateral cross section of the rod is round, so its area would be πd2 divided
by 4, where the Greek letter π (Pi) has a value of 3.1416, and d is the
diameter of the rod. Therefore, the tensile stress would be: Stress
= [50,000 Lbf.] ÷ [π × (2 in.)2 ÷
4] = 15,915.49 Lbf./in.2 Knowing
the stress within the rod, the engineer would next have to select an
appropriate material for the rod that’s strong enough to do the
job. In our case, let’s say we determine that steel is the best
material to use. But what type of steel? Well,
there are engineering handbooks with tables that list the mechanical
properties of all sorts of materials, including metals and plastics, and
along with those properties there is listed their ability to handle
stress. These mechanical properties were determined in laboratory
tests where carefully machined specimens of the materials were subjected to
measured stresses until they deformed and broke apart. They
include yield strength and ultimate strength, and these findings have been
duly recorded so that future engineers need not go through independent
testing of common materials themselves. Yield
strength is the stress that is measured when the test specimen begins to
stretch without any significant increase in force being applied to
it. Ultimate strength is the maximum stress that the material in
the test specimen can withstand before it starts to fail, that is tear apart,
break, collapse. Our
engineer would use the mechanical properties tables that are readily
available to him to select the appropriate steel alloy that would meet our
criteria, that is, has a listed strength high enough above the calculated
15,915.49 Lbf./in.2 tensile
stress to provide a sufficient factor of safety. Factors of safety
are listed in engineering books for yield strength and ultimate strength and
they are selected depending on how the forces are applied to a structural
component or machine part (e.g. steady, varying, or shock). When
strengths of materials analysis involves the solution of complex statics and
dynamics problems, things become a little less
straightforward. And when you are dealing with components having
odd shapes and a combination of stresses, say due to compression and torsion,
things become even more complex. In any case, engineers must have
extensive knowledge of the properties of materials in order to anticipate
factors at play in real world scenarios such as the one we’ve been discussing. Ever
wonder why some steel is hard and brittle, and some is soft and bendable? |