Homogeneous Functions
Homogeneous
To be Homogeneous a function must pass this test:
f(zx,zy) = znf(x,y)
In other words
Homogeneous is when we can take a function:f(x,y)
multiply each variable by z:f(zx,zy)
and then can rearrange it to get this:znf(x,y)
An example will help:
Example: x + 3y
Start with:f(x,y) = x + 3y
Multiply each variable by z:f(zx,zy) = zx + 3zy
Let's rearrange it by factoring out z:f(zx,zy) = z(x + 3y)
And x + 3y is f(x,y):f(zx,zy) = zf(x,y)
Which is what we wanted, with n=1:f(zx,zy) = z1f(x,y)
Yes it is homogeneous!
The value of n is called the degree. So in that example the degree is 1.
Example: 4x2 + y2
Start with:f(x,y) = 4x2 + y2
Multiply each variable by z:f(zx,zy) = 4(zx)2 + (zy)2
Which is:f(zx,zy) = 4z2x2 + z2y2
Factoring out z2:f(zx,zy) = z2(4x2 + y2)
And 4x2 + y2 is f(x,y):f(zx,zy) = z2f(x,y)
Yes 4x2 + y2 is homogeneous.
And its degree is 2.
How about this one:
Example: x3 + y2
Start with:f(x,y) = x3 + y2
Multiply each variable by z:f(zx,zy) = (zx)3 + (zy)2
Which is:f(zx,zy) = z3x3 + z2y2
Factoring out z2:f(zx,zy) = z2(zx3 + y2)
But zx3 + y2 is NOT f(x,y)!
So x3 + y2 is NOT homogeneous.
And notice that x and y have different powers: x3 but y2 which, for polynomial functions, is often a good test.
But not all functions are polynomials. How about this one:
Example: the function x cos(y/x)
Start with:f(x,y) = x cos(y/x)
Multiply each variable by z:f(zx,zy) = zx cos(zy/zx)
Which is:f(zx,zy) = zx cos(y/x)
Factoring out z:f(zx,zy) = z(x cos(y/x))
And x cos(y/x) is f(x,y):f(zx,zy) = z1f(x,y)
So x cos(y/x) is homogeneous, with degree of 1.
Notice that (y/x) is "safe" because (zy/zx) cancels back to (y/x)
Homogeneous, in English, means "of the same kind"
For example "Homogenized Milk" has the fatty parts spread evenly through the milk (rather than having milk with a fatty layer on top.)
Homogeneous applies to functions like f(x), f(x,y,z) etc, it is a general idea.
Homogeneous Differential Equations
A first order Differential Equation is homogeneous when it can be in this form:
In other words, when it can be like this:
M(x,y) dx + N(x,y) dy = 0
And both M(x,y) and N(x,y) are homogeneous functions of the same degree.