Bipolar Junction Transistor (BJT)

A Bipolar Junction Transistor (BJT) has three terminals connected to three doped semiconductor regions. In an NPN transistor, a thin and lightly doped P-type base is sandwiched between a heavily doped N-type emitter and another N-type collector; while in a PNP transistor, a thin and lightly doped N-type base is sandwiched between a heavily doped P-type emitter and another P-type collector. In the following we will only consider NPN BJTs.

Description: Description: transistors1.webp

Description: Description: transistorBJT1.webp

In many schematics of transistor circuits (especially when there exist a large number of transistors in the circuit), the circle in the symbol of a transistor is omitted. The figures below show the cross section of two NPN transistors. Note that although both the collector and emitter of a transistor are made of N-type semiconductor material, they have totally different geometry and therefore can not be interchanged.

Description: Description: transistorBJT2a.webp

Description: Description: transistorBJT2b.webp

All previously considered components (resistor, capacitor, inductor, and diode) have two terminals (leads) and can therefore be characterized by the single relationship between the current going through and the voltage across the two leads. Differently, a transistor is a three-terminal component, which could be considered as a two-port network with an input-port and an output-port, each formed by two of the three terminals, and characterized by the relationships of both input and output currents and voltages. Depending on which of the three terminals is used as common terminal, there can be three possible configurations for the two-port network formed by a transistor:

Description: Description: transistors2.webp

Two voltages Description: Description: $V_{BE}$ and Description: Description: $V_{CB}$ are applied respectively to the emitter Description: Description: $E$ and collector Description: Description: $C$, with respect to the common base Description: Description: $B$, so that the BE junction is forward biased while the CB junction is reverse biased.

Description: Description: CB.webp

Description: Description: CBnpn.webp

Note that the polarity of Description: Description: $V_{BE}$ and direction of Description: Description: $I_B$ associated with the PN-junction between E and B are the same as those associated with a diode, voltage polarity: positive on P, negative on N, current direction: from P to N, but Description: Description: $V_{CB}$ and the direction of Description: Description: $I_C$ associated with the PN-junction between the base and collector are defined oppositely.

The behavior of the NPN-transistor is determined by its two PN-junctions:

The current gain or current transfer ratio is defined as the ratio between the emitter (input) current Description: Description: $I_E$ and the collector (output) current Description: Description: $I_C$

Description: Description: \begin{displaymath}
\frac{I_C}{I_E}\approx \alpha <1,\;\;\;\mbox{i.e.}\;\;\;\;\;
I_C=\alpha I_E
\end{displaymath}


The base current Description: Description: $I_B$ is: 

Description: Description: \begin{displaymath}
I_B=I_E-I_C\approx I_E-\alpha I_E=(1-\alpha)I_E,
\;\;\;\mbox{i.e.}\;\;\;\;\;
I_E=\frac{1}{1-\alpha} I_B
\end{displaymath}

The input current Description: Description: $I_E$ is a function of Description: Description: $V_{CE}$ as well as the input voltage Description: Description: $V_{BE}$, which is much more dominant: 

Description: Description: \begin{displaymath}
I_E=f(V_{BE}, V_{CB})\approx f(V_{BE})=\frac{1}{1-\alpha} I_B
=\frac{1}{1-\alpha} I_0 ( e^{V_{BE}/V_T}-1 )
\end{displaymath}


where 

Description: Description: \begin{displaymath}
I_B=I_0 ( e^{V_{BE}/V_T}-1 )
\end{displaymath}


This relationship between Description: Description: $I_B$ and Description: Description: $V_{BE}$ as the EB junction is very similar to the relationship of Description: Description: $I_D$ and Description: Description: $V_D$ of a diode. Also, we also note higher Description: Description: $V_{CB}>0$ can slightly increase Description: Description: $I_E$.

The output current Description: Description: $I_C$ is a function of the output voltage Description: Description: $V_{CE}$ as well as the input current Description: Description: $I_E$, which is much more dominant: 

Description: Description: \begin{displaymath}
I_C=f(I_E,V_{CB})\approx f(I_E)=\alpha I_E
\end{displaymath}


Here the approximation is based on the assumption that Description: Description: $V_{CB}>0.2V$ (in linear region). As Description: Description: $V_{CB}>0$, i.e., the CB junction is reverse biased, the current Description: Description: $I_C$ depends totally on Description: Description: $I_E$. When Description: Description: $I_E=0$Description: Description: $I_C=I_{CB0}$ is the current caused by the minority carriers crossing the PN-junction. This is similar to the diode current-voltage characteristics seen before, except both axes are reversed (the polarity of Description: Description: $V_{CB}$ and the direction Description: Description: $I_C$ are oppositely defined). When Description: Description: $I_E$ is increased, Description: Description: $I_C=\alpha I_E$ is increased correspondingly. Higher Description: Description: $V_{CB}$ can slightly increase Description: Description: $I_C$. As Description: Description: $I_C=\alpha I_E<I_E$, CB configuration does not have current-amplification effect. However, if Description: Description: $V_{BE}$ is held constant, Description: Description: $I_E$ and therefore Description: Description: $I_C$ will also be held constant, i.e., CB transistor circuit can be used as a current source.

Description: Description: TransistorCBplots.webp

Two voltages Description: Description: $V_{BE}$ and Description: Description: $V_{CE}$ are applied respectively to the base Description: Description: $B$ and collector Description: Description: $C$ with respect to the common emitter Description: Description: $E$. As typically Description: Description: $V_{CE} > V_{BE}$, the BE junction is forward biased but the CB junction is reverse biased, same as the CB configuration. The voltages of CB and CE configurations are related by: 

Description: Description: \begin{displaymath}
V_{CE}=V_{CB}+V_{BE},\;\;\;\;\;\mbox{or}\;\;\;\;\; V_{CB}=V_{CE}-V_{BE}
\end{displaymath}


Description: Description: CE1.webp

Description: Description: CEnpn.webp

The base current Description: Description: $I_B$ is treated as the input current, and the collector current Description: Description: $I_C$ is treated as the output current: 

Description: Description: \begin{displaymath}
I_C=\alpha I_E = \alpha (I_C+I_B)
\end{displaymath}


Solving this equation for Description: Description: $I_C$, we get the relationship between the output Description: Description: $I_C$ and the input Description: Description: $I_B$

Description: Description: \begin{displaymath}
I_C=\frac{\alpha}{1-\alpha} I_B =\beta I_B
\end{displaymath}


where we have defined the CE current gain, the ratio of the output current Description: Description: $I_C$ and the input current Description: Description: $I_B$

Description: Description: \begin{displaymath}
\beta=\frac{\alpha}{1-\alpha}\approx\frac{I_C}{I_B}
\end{displaymath}


The two parameters Description: Description: $\alpha$ and Description: Description: $\beta$ are related by any of the following: 

Description: Description: \begin{displaymath}\beta=\frac{\alpha}{1-\alpha},\;\;\;\;\;\;\alpha=\frac{\beta}...
...+\beta=\frac{1}{1-\alpha},\;\;\;\;\;1-\alpha=\frac{1}{1+\beta} \end{displaymath}


For example, if Description: Description: $\alpha=0.99$, then Description: Description: $\beta=0.99/(1-0.99)=99$.

The CE configuration can be considered as a 2-port circuit. The input port is formed by the base and emitter, the output port is formed by the collector and emitter. The relationships between the current and voltage of both the input and output ports are described by the following input and output characteristics.

Same as in the case of common-base configuration, the EB junction of the common-emitter configuration can also be considered as a forward biased diode, the current-voltage characteristics is similar to that of a diode: 

Description: Description: \begin{displaymath}
I_B=f(V_{BE},V_{CE})\approx f(V_{BE})=I_0 ( e^{V_{BE}/V_T}-1 )
\end{displaymath}


Description: Description: $V_{CE}$ has little effect on Description: Description: $I_B$.

Description: Description: \begin{displaymath}
I_C=f(I_B,V_{CE})\approx f(I_B)=\beta I_B\;\;\;\;\;\;\;\;\;\;\mbox{(in linear region)}
\end{displaymath}


Higher Description: Description: $V_{CE}>0$ can slightly increase Description: Description: $I_C$.

The CB junction is reverse biased, the current Description: Description: $I_C=\beta I_B$ depends on the current Description: Description: $I_B$. When Description: Description: $I_B=0$Description: Description: $I_C=0$, the current caused by the minority carriers crossing the PN-junctions. When Description: Description: $I_B$ is increased, Description: Description: $I_C$ is correspondingly increased by Description: Description: $\beta$ fold.

Description: Description: TransistorCEplots.webp

The relationship between the input and output currents of both CB and CE configurations is summarized below:

Description: Description: \begin{displaymath}
\left\{ \begin{array}{l}
I_{out}=I_C=\alpha I_E=\alpha I_{...
..._B=I_E-I_C=I_E-\alpha I_E=(1-\alpha)I_E
\end{array} \right.
\end{displaymath}


Description: Description: CommonBase.webp

Description: Description: \begin{displaymath}
\left\{ \begin{array}{l}
I_{out}=I_C=\beta I_B=\beta I_{i...
... gain})
\\
I_E=I_C+I_B=(\beta+1) I_B
\end{array} \right.
\end{displaymath}


Description: Description: CommonEmitter.webp

The collector characteristics of the common-base (CB) and common-emitter (CE) configurations have the following differences:

Description: Description: InputOutputChar.webp

Description: Description: transistortemp.webp

Various parameters of a transistor change as functions of temperature. For example, Description: Description: $\beta$ increases along with temperature.