Science in general and Physics in particular are concerned
with relationships. Cause and effect is the focus of science. Nature is probed
in order to find relationships and mathematical patterns. Scientists modify a
set of conditions to see if there is a pattern of behavior in
another set of measurable quantities. The goal is to answer the question of how
does a change in a set of variables or conditions causally affect an observable
outcome? In Physics, this search for cause and effect leads to questions like:
How
does a force affect the acceleration of an object?
How does the mass of an object affect its acceleration?
How does the speed of a falling object affect the amount of
air resistance that it experiences?
How does the distance from a page to a light bulb affect the
amount of light that illuminates the paper's surface?
How does the frequency of a sound wave affect the speed at
which the sound wave moves?
How does the distance between two charged objects affect the
force of attraction or repulsion that they encounter?
This search for cause and effect often leads to conclusive evidence that two
variables are causally related (or not causally related). Careful observation
and measurement might indicate that a pattern exists in which an increase in
one variable always causes another measurable quantity to increase. This type
of cause-effect relationship is described as being a direct relationship.
Observation might also indicate that an increase in one variable always causes
another measurable quantity to decrease. This type of cause-effect relationship
is described as being an inverse relationship.
Inverse relationships are common in nature. In
electrostatics, the electrical force between two charged objects is inversely
related to the distance of separation between the two objects. Increasing the
separation distance between objects decreases the force of attraction or
repulsion between the objects. And decreasing the separation distance between
objects increases the force of attraction or repulsion between the objects. Electrical
forces are extremely sensitive to distance. These observations are commonly
made during demonstrations and lab experiments. Consider a charged plastic golf
tube being brought near a collection of paper bits at rest upon a table. The
electrical interaction is so small at large distances that the golf tube does
not seem to exert an influence upon the paper bits. Yet if the tube is brought
closer, an attractive interaction is observed and the strength is so
significant that the paper bits are lifted off the table. In a similar manner,
charged balloons are observed to exert their greatest influence upon other
charged objects when the separation distance is reduced. Electrostatic force
and distance are inversely related.
The pattern between electrostatic force and distance can be
further characterized as an inverse square relationship. Careful
observations show that the electrostatic force between two point charges varies inversely with the square of
the distance of separation between the two charges. That is, the factor by
which the electrostatic force is changed is the inverse of the square of the
factor by which the separation distance is changed. So if the separation
distance is doubled (increased by a factor of 2), then the electrostatic force
is decreased by a factor of four (2 raised to the second power). And if the
separation distance is tripled (increased by a factor of 3), then the
electrostatic force is decreased by a factor of nine (3 raised to the second
power). This square effect makes distance of double
importance in its impact upon
electrostatic force.
The inverse square relationship between electrostatic force
and separation distance is illustrated in the table below.
Row |
Separation Distance |
Electrostatic Force |
1 |
20.0 cm |
0.1280 N |
2 |
40.0 cm |
0.0320 N |
3 |
60.0 cm |
0.0142 N |
4 |
80.0 cm |
0.0080 N |
5 |
100.0 cm |
0.0051 N |
The above values illustrate a pattern: as the separation
distance is doubled, the electrostatic force is decreased by a factor of four.
For instance, the distance in Row 2 is twice the distance of Row 1; and the
electrostatic force in Row 2 is one-fourth the electrostatic force of Row 1. A
comparison of Row 1 and Row 3 illustrate that as the distance is increased by a
factor three, the force is decreased by a factor of nine. The distance in Row 3
is three times that of Row 1 and the force in Row 3 is one-ninth that of Row 1.
A similar comparison of Rows 1 and Row 4 illustrates that as the distance is
increased by a factor of four, the electrostatic force is decreased by a factor
of 16. The distance in Row 4 is four times that of Row 1 and the force in Row 4
is one-sixteenth that of Row 1.
The inverse square relationship between force and distance is
expressed in the Coulomb's law equation for electrostatic force. In the previous section of
Lesson 3, Coulomb's law was stated as
This equation is often used as a recipe for algebraic problem
solving. This type of use of the Coulomb's law equation was the subject of the previous section of
Lesson 3. The equation shows that the distance squared
term is in the denominator of the equation, opposite the force. This
illustrates that force is inversely proportional to the square of the distance.
Understanding this inverse proportionality allows one to use the
equation as a guide to thinking about how a variation in one quantity (e.g.,
distance) affects another quantity (Force). Equations can be more than merely
recipes for algebraic problem solving; they can be "guides to
thinking." Check your understanding of Coulomb's law as a guide to
thinking by answering the questions below. When finished, click the button to
check your answers.
Use your understanding of charge to answer the following
questions. When finished, click the button to view the answers.
1. Two charged objects have a repulsive force of 0.080 N. If
the charge of one of the objects is doubled, then what is the new force?
Answer: 0.160 N
Explanation:
Electrostatic force is directly related to the charge of each object. So if the
charge of one object is doubled, then the force will become two times greater.
Two times 0.080 N is 0.160 N.
2. Two charged objects have a repulsive force of 0.080 N. If
the charge of both of the objects is doubled, then what is the new force?
Answer: 0.320 N
Explanation:
Electrostatic force is directly related to the charge of each object. So if the
charge of both objects is doubled, then the force will become four times greater.
Four times 0.080 N is 0.320 N.
3. Two charged objects have a repulsive force of 0.080 N. If
the distance separating the objects is doubled, then what is the new force?
Answer: 0.020 N
Explanation: The
electrostatic force is inversely related to the square of the separation
distance. So if d is two times larger, then F is four times smaller - that is,
one-fourth the original value. One-fourth of 0.080 N is 0.020 N.
4. Two charged objects have a repulsive force of 0.080 N. If
the distance separating the objects is tripled, then what is the new force?
Answer: 0.00889 N
Explanation: The
electrostatic force is inversely related to the square of the separation distance.
So if d is three times larger, then F is nine times smaller - that is,
one-ninth the original value. One-ninth of 0.080 N is 0.00889 N.
close
5. Two charged objects have an attractive force of 0.080 N.
If the distance separating the objects is quadrupled, then what is the new
force?
Answer: 0.0050 N
Explanation: The
electrostatic force is inversely related to the square of the separation
distance. So if d is four times larger (quadrupled), then F is 16 times smaller
- that is, 1/16-th the original value. One-sixteenth of 0.080 N is 0.0050 N.
6. Two charged objects have a repulsive force of 0.080 N. If
the distance separating the objects is halved, then what is the new force?
Answer: 0.320 N
Explanation: The
electrostatic force is inversely related to the square of the separation
distance. So if d is two times smaller, then F is four times larger. Four times
0.080 N is 0.320 N
7. Two charged objects have a repulsive force of 0.080 N. If
the charge of one of the objects is doubled, and the distance separating the
objects is doubled, then what is the new force?
Answer: 0.040 N
Explanation: The
electrostatic force is directly related to the product of the charges and
inversely related to the square of the separation distance. Doubling one of the
charges would serve to double the force. Doubling the distance would serve to
reduce the force by a factor of four. The combined affect of
these two variations would be to decrease the force by a factor of two -
changing it from 0.080 N to 0.040 N
8. Two charged objects have a repulsive force of 0.080 N. If
the charge of both of the objects is doubled and the distance separating the
objects is doubled, then what is the new force?
Answer: 0.080 N
Explanation: The
electrostatic force is directly related to the product of the charges and
inversely related to the square of the separation distance. Doubling both of
the charges would serve to quadruple the force. Doubling the distance would
serve to reduce the force by a factor of four. The combined affect of these two variations would be to not change
the force at all; it remains as 0.080 N.
9. Two charged objects have an attractive force of 0.080 N.
If the charge of one of the objects is increased by a factor of four, and the
distance separating the objects is doubled, then what is the new force?
Answer: 0.080 N
Explanation: The
electrostatic force is directly related to the product of the charges and
inversely related to the square of the separation distance. Quadrupling one of
the charges would serve to quadruple the force. Doubling the distance would
serve to reduce the force by a factor of four. The combined affect of these two variations would be to not alter
the force at all; it would remain as 0.080 N.
10. Two charged objects have an attractive force of 0.080 N.
If the charge of one of the objects is tripled and the distance separating the
objects is tripled, then what is the new force?
Answer: 0.0267 N
Explanation: The
electrostatic force is directly related to the product of the charges and
inversely related to the square of the separation distance. Tripling one of the
charges would serve to triple the force. Tripling the distance would serve to
reduce the force by a factor of nine. The combined affect of
these two variations would be to make the force 3/9-ths or 1/3-rd the original
value. One-third of 0.080 N is 0.0267 N.