Equations for the Horizontal Motion of a Projectile

The above equations work well for motion in one-dimension, but a projectile is usually moving in two dimensions - both horizontally and vertically. Since these two components of motion are independent of each other, two distinctly separate sets of equations are needed - one for the projectile's horizontal motion and one for its vertical motion. Thus, the three equations above are transformed into two sets of three equations. For the horizontal components of motion, the equations are

                                                     x = v_ix•t + 0.5*a_x*t²                                                                

v_fx = v_ix + a_x•t

v_fx² = v_ix² + 2*a_x•x

where	x = horiz. Displacement	ax = horiz. acceleration	t = time
	vfx = final horiz. velocity	vix = initial horiz. velocity

Of these three equations, the top equation is the most commonly used. An application of projectile concepts to each of these equations would also lead one to conclude that any term with a_x in it would cancel out of the equation since a_x = 0 m/s/s. Once this cancellation of axterms is performed, the only equation of usefulness is:

x = v_ix•t

Equations for the Vertical Motion of a Projectile

For the vertical components of motion, the three equations are

y = v_iy•t + 0.5*ay*t²

v_fy = v_iy + ay•t

v_fy² = v_iy² + 2*ay•y

where	y = vert. displacement	ay = vert. acceleration	t = time
	vfy = final vert. velocity	viy = initial vert. velocity

In each of the above equations, the vertical acceleration of a projectile is known to be -9.8 m/s/s (the acceleration of gravity). Furthermore, for the special case of the first type of problem (horizontally launched projectile problems), v_iy = 0 m/s. Thus, any term with v_iy in it will cancel out of the equation.

The two sets of three equations above are the kinematic equations that will be used to solve projectile motion problems.