Inertial frames, Newtonian mechanics
Inertial framesNewton's laws work - sometimes. At other times, they appear not to work. Frames of reference in which Newton's laws of motion are observed are called Inertial Frames. For instance, the surface of the Earth is almost* an inertial frame. When we analyse the behaviour of objects with respect to the Earth, we nearly* always find that F = ma. Further, in the particular case where F = 0, objects maintain constant velocity. * The 'almost' and 'nearly' are inserted above because of the Earth's own motion. The daily rotation is quite slow: only one turn per day is 0.004 degree per second: this is why we cannot feel it. However, if we could observe motion over many minutes, we should notice that, for an object subject to negligible external forces, measurements made with respect to the laboratory frame show a very small acceleration. This acceleration is best considered as the acceleration of the laboratory with respect to the object: the result of the rotation of the laboratory, which turns with the Earth. The Earth is approximately, but not quite, an inertial frame. See the Foucault pendulum and coriolis forces for a more detailed discussion of this point. Non inertial frames. In measurements made with respect to some other frames of reference, Newton's laws appear to be violated. For example, when the bus goes round a corner, a standing passenger who is not holding onto a rail seems to find himself accelerating sideways. If you try throwing and catching balls on a merry-go-round, you'll also observe some apparent violations of Newton's laws. Try this animation:
Zoe throws a ball from the centre of the a merry-go-round. To Zoe, turning clockwise with the merry-go-round (picture at left), the ball seems to curve to the left - it travels anti-clockwise. To an observer who is not rotating (e.g. someone in a helicopter above, picture at right, or to Jasper, sitting on the ground), the merry-go-round turns clockwise and the ball travels in a vertical plane (and thus a straight line, seen from above).
More on the Galilean principle of relativityThis may be stated in a few different ways:
One could also state it this way:
Why are the laws of physics the same in the train and on the platform?The Galilean principle of relativity follows from a simple set of transformation equations and a few deceptively simple assumptions. These assumptions are so simple that most of us (though not Newton) would be likely to make them without thinking. For simplicity, let's confine all motion to the x direction. Suppose the train is moving with velocity v (in the x direction). To be concrete, let's suppose that the train is moving at 30 m/s. After one second, the train is 30 metres further on. Now consider a passenger walking with constant velocity u = 1 m/s along the aisle, towards the front of the train. After one second, she is 1 metre further down the aisle. How far has she moved with respect to the platform? This looks like a simple question, but to answer it we need to make some assumptions about time and space. Let's assume, as Galileo and Newton quite reasonably did, that time is the same for all observers, provided that they have synchronised their clocks somewhere at some time, and that rulers have the same lengths for all observers. Okay, while I was carefully make my assumptions you beat me to it: the train has travelled 30 metres in the second, she is one metre further down the aisle, so she has travelled 31 metres with respect to the platform. She is travelling at v + u. In other words Now imagine that our passenger breaks into a run: she is accelerating. At one moment she is walking at 1 metre per second down the aisle, and a second later she is doing 3 metres per second, so her acceleration a in the train (we'll assume it constant) is 2 metres per second per second. What does the man on the platform see? Well, making the same assumptions as before, he saw her first at 31 m/s, then a second later at 33 m/s, so he reckons that she accelerates at 2 metres per second per second also. This is a quite important point: observers in the train and on the platform disagree about the position and velocity of our runner, but not about her acceleration. Acceleration is the same whether observed from the train or from the station. (Remember that the train is travelling in a straight line at constant speed - our argument only applies to uniform relative motion.) So let's make more assumptions, no more unreasonable than those made earlier. We assume that both observers can agree on what forces (magnitude F) occur between her feet and the floor of the train, and that they agree on her mass m. Consequently, if F=ma is true for one of them, then F=ma is true for the other. |