Ac load line analysis

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The DC Load Line is simple to explain, for a given circuit the relation between VCE and IC must comply to the KVL relationship for that circuit.

In the graph we can choose a Q point, and then see if we superimpose an AC signal on top of the DC voltage then the VC will follow accordingly, and we can determine the maximum output swing.

The AC Load Line confuses me however. Because when I determine this line using the AC equivalent circuit model and KVL across the vce loop, the load line now goes through zero on a graph.

ic = - vce / (RC // RL)

Then I understand to get the true load line of the circuit, I must superimpose the AC Load line on the Q point, and preferably use the middle of the AC LL as the Q point.

I then get this:

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