Ac load line analysis
The DC Load Line is simple to explain, for a given circuit the relation
between VCE and IC must comply to the
KVL relationship for that circuit.
In the graph we can choose a Q point, and then see if
we superimpose an AC signal on top of the DC voltage then the VC will follow accordingly, and we can determine
the maximum output swing.
The AC Load Line confuses me however. Because when I
determine this line using the AC equivalent circuit model and KVL across the vce loop,
the load line now goes through zero on a graph.
ic = - vce /
(RC // RL)
Then I understand to get the true load line of the
circuit, I must superimpose the AC Load line on the Q point, and preferably use
the middle of the AC LL as the Q point.
I then get this: