Operational
amplifiers, or opamps, are one of the most
fundamental building blocks an electrical engineer can employ in circuit
designs. There are a ton of useful applications foropamps.
This article will go over just a few basic circuits you can implement in your
designs!
The first circuit is so
simple that it almost looks a little crazy:
Figure 1:
Voltage Follower
This circuit is referred to
as a voltage follower, and it behaves like this:
Vin=VoutVin=Vout
On face, this isn't super
useful. Why would I pay a few extra cents for an opamp when
it looks like a wire would do the same job between two components? The answer
is simple once you know a few simple things about opamps.
When you start to break down a circuit with opamps,
two basic principles should be at the forefront of your mind:
1. The opamp's input
terminals, V+ and V-, draw no current.
2. The voltage of V+ and V- are always
equal. This property is sometimes called the virtual short
approximation.
Looking at the first rule, we
can see that our voltage follower circuit is not drawing any current at the
input terminal connected to V+. This is really just a way of saying that V+ has
a really high impedance - in fact, since we're talking about ideal opamps, we tend to just say that it has infinite input
impedance. In practice, this has some pretty neat implications: if V+ isn't
drawing any current, then it means that we could connect Vin to any node in any circuit and measure it without
modifying the original circuit. We wouldn't have to go through the
tedious rigamarole of solving a bunch of
new equations for node voltages and mesh currents, because we wouldn't be
disturbing either of them by adding a voltage follower. Pretty cool, huh?
(Note: Like most rules, there
are some exceptions to these opamp rules.
For the duration of this article, we're going to ignore these exceptions - they
would get in the way of analyzing our
voltage follower.)
Instead of taking a direct
measurement at Vin in our hyptothetical circuit, we'd measure instead at Vout. This is the second rule of opamps in
effect - the voltages of V+ and V- are always considered to be equal. Since
we've connected V- and and the opamp'soutput, we can extend this a step further, and say
that Vout = V- = V+ due to the virtual
short approximation.
Using voltage followers
provides a really easy way to interface different circuits that have different
impedances. Cool! What else can we do with opamps?
As their name suggests, opamps are amplifiers. They can amplify signals by a
certain ratio of input to output. This ratio is commonly referred to as the
gain of an operational amplifier. In a perfect world, an opamp's gain would be infinite - so high that it could
amplify any signal level to any other signal level. This isn't the case in the
real world, but we'll consider it a fact while we analyze the
next circuit: an inverting amplifier.
Figure 2:
Inverting Amplifier
Let's walk through this
circuit's operation step by step. First, let's apply our two opamp rules to figure out some node voltages of this
circuit. The simplest one to apply is the virtual short approximation, where V+
and V- are always at the same voltage. We can see that V+ is tied to ground;
therefore, V- must also be at ground. What about the current going into and out
of node V-? By Kirchoff's current law, we
know that the sum of all currents at that node must be as follows:
iRin+iRf+iV−=0iRin+iRf+iV−=0
Initially, this looks like it
might take some work to solve, as this equation has three unknowns. But does
it? If you recall the opamp rules stated
earlier, you'll see that we get one term of this equation for free: opamp inputs don't draw any current! Therefore, we
know that iV- is equal to zero. We can then
rearrange that equation into the following form:
iRin=−(iRf)iRin=−(iRf)
Since V- is tied to ground by
the virtual short, Ohm's law allows us to substitute out these currents as
voltages and resistances:
VinRin=−VoutRfVinRin=−VoutRf
Which, with a little algebra,
gets us back to where we started:
Vout=Vout=
−VinRfRin−VinRfRin
It's pretty clear why this
circuit is useful - it allows you to apply a linear gain to an input and output
by choosing (Rf/Rin) to
form any ratio you want. The circuit also has the added bonus of allowing you a
lot of control over its input impedance - since you're free to choose the
resistor value of Rin, you can crank it up as
high or as low as needed to fit whatever output impedance you need to match it
to!
Why do we need a resistor
network to achieve this behavior? To understand
that, we'll have to understand a little bit more of how an opamp works. An opamp is
a type of voltage amplifier. In the ideal case, an opamp provides
infinite gain - it can amplify any voltage to any other voltage level. We can
scale the opamp's infinte gain
by using a resistor network that connects the input node, V-, and the output
node. By connecting the opamp output to an
input, we're using a process called _feedback_ to adjust the output voltage to
a desired level. Feedback is a really important EE concept, and complex enough
to warrant a whole article dedicated to the topic. For now, it's enough to
understand the basic principle as it applies to opamps:
by connecting the output to an input, you can modify a circuit's behavior in really useful ways.
Let's see what happens when
we start fooling around with the basic inverting amplifier design. What happens
if we swap out the feedback network to the other input pin, V-?
Figure 3: What does this circuit do?
We can go through the same
series of steps as we did before with the inverting amplifier, but we start
substituting in voltages at the V- node. Due to the virtual short
approximation, V- = V+ = Vin. As a result, we can
write the following equation for the current going through Rg:
i=VinRgi=VinRg
Since we know that the opamp isn't drawing any current, we know that the
current through Rg and Rf must be equal, which allows us to write this
equation:
Vout−V−=iRf⇒Vout−V−=VinRfRgVout−V−=iRf⇒Vout−V−=VinRfRg
The virtual short
approximation lets us get rid of V-, since we know it is equal to Vin.
Vout−Vin=VinRfRgVout−Vin=VinRfRg
And with a bit of algebraic
rearranging, we get the following:
Vout=(1+RfRg)VinVout=(1+RfRg)Vin
Unlike the previous circuit,
the gain of this circuit is nonnegative. As a result, this circuit is called
a noninverting amplifier: It provides a linear gain, but with a
positive sign. Unlike the previous noninverting amplifier, it cannot provide
any gain less than unity - it's impossible to set the feedback network any
lower! On the other hand, this circuit does provide one thing that the
inverting amplifier does not. Since the output is positive, it is in phase with
the input. The inverting amplifier, by virtue of applying a negative gain, is
shifting the output signal by 180 degrees. The noninverting amplifier doesn't
do this!
Opamps are really versatile circuit
components. This article barely scratches the surface of what can be done with
them - the range of functionality that they can bring to bear is enormous. What
are some of the other circuits you can make with them? Have any cool circuits
you've built with opamps? Leave us a note in the
comment section and tell us about it!